a men has a list of seven appetizers. your party will choose three. which of the following represents the number of possible choices? 7!/3!, 7c3, or 7!-3!.thanks.
2007-04-11 11:31:02 · 5 answers · asked by catmuffin 1 in Science & Mathematics ➔ Mathematics
7C3
2007-04-11 11:35:06 · answer #1 · answered by ironduke8159 7 · 0⤊ 1⤋
7c3 because the order of the apetizers doesn't matter
7c3=7!/((3!(7-3)!)=35
2007-04-11 18:37:56 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
I think it's 7c3 because you wouldn't have to divide or subtract.
2007-04-11 18:37:13 · answer #3 · answered by Anna <3 2 · 0⤊ 0⤋
Count me in. Amen to a list of seven appetizers.
2007-04-11 18:37:27 · answer #4 · answered by ? 6 · 0⤊ 0⤋
Since the order does not matter, use combinations.
7c3
7!/(3!*4!) = 35 possibilities
2007-04-11 18:35:24 · answer #5 · answered by BB 2 · 0⤊ 0⤋