If 20.00 ml of 0.2019 M HCl requires 39.63 mL of a NaOH sol'n for complete neutralization...
2007-04-11 10:57:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
what you should know before starting any calculations.
1. HCl reacts in a 1:1 ratio with NaOH
so what is the molarity of 20ml of 0.2019M HCl
well; 1000ml = 0.2019M HCl
so 20ml will contain (20/1000) x 0.2019 = 0.004038moles
Therefore it will take 0.004038 moles of NaOH to neutralize the HCl.
so that would mean that 39.63 ml contains 0.004038moles of NaOH.
so 1000ml will contain (1000/39.63) x 0.004038
=0.1018moles
2007-04-11 11:12:21 · answer #1 · answered by curious 2 · 0⤊ 0⤋
moles = 0.2019 M HCL x0 .02L
=0.004038
then concentration is just mole/volume
=0.004038moles/ 0.03963 L
=0.1019 M
2007-04-11 18:03:46 · answer #2 · answered by devilkidjin 2 · 0⤊ 0⤋
(20/39.63) x 0.2019
2007-04-11 18:04:10 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋