608mm Hg is held in a container with the volume of 545 cm3. The volume of the container is increased to 1065?

Question

cm3 without a change in temperature. Find the new pressure of the gas? (new question)>Calculate the decrease in temperature when 2.00 L at 20.0 Celsius is compressed to 1.00L?

Answer 1

1st Q: Boyle's law (see ref.) says that at constant temperature, P1V1=P2V2. So 608*545 = P2*1065.
2nd Q: This is a complex problem involving the 1st law of thermodynamics. The 1st law deals with two theoretical types of compression. Isothermal compression occurs at infinitesimal speed, and the temperature doesn't rise because the heat is lost quickly relative to its rate of generation. Adiabatic compression is so fast that no heat is lost at all and the maximum possible temperature and pressure increases are obtained for the work done. Because of the higher pressure during the compression stroke, more work is done. In either case, the temperature and pressure obey the combined gas law, that for a constant quantity of gas, P1V1/T1 = P2V2/T2 . P2 will increase from P1 to P1 * V1/V2 * T2/T1. In the isothermal case T2 = T1, so the simplification embodied in Boyle's law applies.
Real-world compression is between isothermal and adiabatic. Some heat is lost during compression. After compression is complete, as the system cools and loses energy, the temperature will decrease toward ambient (i.e., T2=T1) and pressure will decrease toward P1V1/V2. In cyclic machinery such as an air compressor, these equilibrium points will not be reached. Finally, answering your question, the temperature will increase, not decrease, but to what amount cannot be stated from the information given.

Answer 2

2576