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3 answers

F(x) =
integral [1 to x] (t^(1/2) dt) =
[1 to x] ( 2/3 * t^3/2) =

2/3 * x^3/2 - 2/3 =
2/3 (x^3/2 - 1)

2007-04-11 10:35:18 · answer #1 · answered by iluxa 5 · 0 0

(2/3)(x^(3/2) - 1) using the same reasoning as the answer to your previous question

2007-04-11 17:34:56 · answer #2 · answered by Quadrillerator 5 · 0 0

f(x) = 2/3t^3/2 evaluated from 1 to x
f(x) = 2/3x^3/2 - 2/31^3/2
f(x) = 2/3 x^3/2 -2/3

2007-04-11 17:40:07 · answer #3 · answered by ironduke8159 7 · 0 0

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