2007-04-11 08:57:09 · 16 answers · asked by porcha b 1 in Science & Mathematics ➔ Mathematics
2/3y - 6 = 2
2/3y - 6 + 6 = 2 + 6
2/3y = 8
3(2/3y) = 3(8)
2y = 24
2y / 2 = 24 / 2
y = 24 / 2
y = 12
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2007-04-11 10:15:46 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
2/3y-6=2
2/3y-6+6=2+6
2/3y=8
(3/1)(2/3y)=8(3)
2y=24
2y/2=24/2
y=12
Just remember that an equation is like a see saw, what you add or take away from one side must also be added or taken away from the other side.
Show your work and then if there is a problem, you will be able to back up and find where the mistake was made.
If you are having trouble with your homework, why don't you tell your teacher?
2007-04-11 16:04:29 · answer #2 · answered by cat14675 3 · 1⤊ 0⤋
if your formula was (2/3y) - 6 = 2 then y=1/12 or 0.08333333
if your formula was 2/(3y-6) = 2 then y= 7/3 or 2.3333333
2007-04-11 16:19:26 · answer #3 · answered by smileytulip_jeh 2 · 0⤊ 0⤋
12
2007-04-11 16:00:14 · answer #4 · answered by jazz 2 · 1⤊ 2⤋
2/3 y = 2 + 6
2/3 y = 8
y = 8 * 3/2 = 12
2007-04-11 16:09:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y = 12
2007-04-11 15:59:40 · answer #6 · answered by Anonymous · 1⤊ 2⤋
y=1/12 is the correct answer
2/3y=8 (multiply both sides with 3y)
3y(2/3y)=24y
2=24y
y=2/24
y=1/12
2007-04-11 16:18:50 · answer #7 · answered by kingsearch 2 · 0⤊ 0⤋
2/3y-6=2 ________original equation, assuming (2/3)y-6 = 2
2/3y = 8 _________grouping like terms
y = 8 x 3 / 2______remove fractional coefficient by multiplying both sides of equation by inverse of coefficient
y = 12
2007-04-11 16:00:11 · answer #8 · answered by The Oracle 6 · 0⤊ 2⤋
[2/(3y)]-6=2
[2/(3y)] = 8
Multiplying both members by (3y):
2 = 24y
y = 1/12
2007-04-11 16:01:40 · answer #9 · answered by Anonymous · 1⤊ 2⤋
2/3y-6 =2
2y-18=6 ( Get rid of denominator x both sides by 3)
2y=24 ( Add 18 to both sides)
y=12 ( Divide by 2)
2007-04-11 16:01:08 · answer #10 · answered by fireflyspace23 3 · 0⤊ 2⤋