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I need help. the problem says .
Find an equation, in slope-intercept form, that passes through point (1,-5) with slope -1

can you help fast?

2007-04-11 08:51:43 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

Slope-intercept form is y = mx + b. Here m is the slope, so this means the equation is y = -x + b for some value "b". Plug in (1, -5) and you can solve for b:
-5 = -1 + b, so -4 = b

Thus the equation is y = -x - 4.

2007-04-11 08:58:36 · answer #1 · answered by Anonymous · 0 0

First, start with point-slope form:
y + 5 = -1(x - 1)
Then convert to slope-intercept:
y = -x + 1 - 5
y = -x - 4

The slope is -1, and the intercept is -4.

Plug in (1, -5) to check:
-5 = -1 - 4
-5 = -5

2007-04-11 08:55:45 · answer #2 · answered by computerguy103 6 · 0 0

y+5=-(x-1)
y=-x-4

2007-04-11 09:00:27 · answer #3 · answered by katsaounisvagelis 5 · 0 0

slope intercept form

y = mx + b

- 5 = - 1(1) + b

- 5 = - 1 + b

- 5 + 1 = - 1 + b + 1

- 4 = b

- - - - - - -

The equation

y = - 1x - 4

- - - - - - - - - -s-

2007-04-11 10:21:12 · answer #4 · answered by SAMUEL D 7 · 0 0

using point-slope form:

y - (-5) = -1( x - 1)
y + 5 = -x + 1
y = -x - 4

2007-04-11 08:58:14 · answer #5 · answered by Philo 7 · 0 0

y-ysub1=m(x-xsub1) plug in the numbers
y--5=-1(x-1)
y+5=-x+1 subtract 5 from both sides
y= -x-4

2007-04-11 09:00:05 · answer #6 · answered by Justina 3 · 0 0

slopes the rise over the run

delta x/delta y

2007-04-11 08:57:37 · answer #7 · answered by *Kara* 2 · 0 0

m = -1
x = 1
y = -5

y=mx+b
-5=-1*1+b
-5=-1+b
-4=b
y=-1x-4
y = -x - 4

2007-04-11 08:54:53 · answer #8 · answered by bourqueno77 4 · 0 0

slope m=( y-y1)/(x-x1)
-1 = (y --5)/(x-1)
1-x = y +5
y =-x -4 or y= -(x+4)

2007-04-11 09:03:29 · answer #9 · answered by bignose68 4 · 0 0

sub.-in everything in y=mx=b and slove for b=?

b= -4
so... y= -x-4

2007-04-11 09:04:34 · answer #10 · answered by Luna_5 2 · 0 0

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