2007-04-11 08:44:22 · 15 answers · asked by Anonymous in Entertainment & Music ➔ Television
Melinda. If not her then Jordin.
2007-04-11 09:03:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I have to say Lakeisha. Melinda is a better singer but she doesn't have the personality that Lakeisha does. I like Jordan a lot too, but I don't think she has the voice the other two do.
2007-04-11 15:52:53 · answer #2 · answered by kerfitz 6 · 0⤊ 1⤋
Lakeisha
2007-04-11 15:48:36 · answer #3 · answered by deb 7 · 0⤊ 0⤋
definetly lekisha!!! she is the best on that show! and i wish everyone would stop hatin' on sanjaya! i like him! he's too sweet to make fun of. and his hair ROX!!! i hate hayley tho! god the only reason she's still on there is cuz she wears those tiny little shorts! all's she is is a little slutty hobag whore!!! i also like blake, melinda, and jordin. i wish jared cotter and brandon were still on there! i loved those guys!!!!
2007-04-11 15:57:41 · answer #4 · answered by ? 3 · 0⤊ 0⤋
I really hope it's Blake........He is so cute and really talented! Melinda is also good. I think that Blake and Melinda should be in the Finals, and Blake should win!! = )
I hope Sanjaya gets out soon, because he is so bad, and wierd.
2007-04-11 16:04:26 · answer #5 · answered by SoCalGirl<33 3 · 1⤊ 2⤋
I wish they would take it off the air and put something more intelligent in its place... like Gilligan's Island reruns or Mexican Karaoke.
2007-04-11 15:52:38 · answer #6 · answered by Surveyor 5 · 0⤊ 1⤋
although i wasnt really into her performance last night i would love lakesha to win...they need to hurry up and boot haley off already and her buddy sanjaya
2007-04-11 15:47:56 · answer #7 · answered by lucy l 2 · 0⤊ 1⤋
Melinda should win.She has the voice,she doesn't dress trashy,and she is entertaining.
2007-04-11 15:58:59 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Melinda Doolittle. She's the best out of all of them.
2007-04-11 15:48:33 · answer #9 · answered by Anonymous · 0⤊ 1⤋
Sanjaya.
2007-04-11 15:59:17 · answer #10 · answered by t c 3 · 1⤊ 2⤋