math problem?

Question

can u show me how to factor this one ? plz

-2x^2 - 12x -14

Answer 1

take out the -2 you have -2(x^2+6x+7)
it cant be factored from there unless u use quadractic formula which is [-b+- sq. root (b^2-4ac)]/(2a)

a=1
b=6
c=7
those are the coefficients in front of each of the terms.

Answer 2

-2x^2 - 12x -14 you can only factor out the -2
-2(x^2+6x+7)

Answer 3

Destroy the negative two. this gets you to
-2(x^2+6x+7)
But It looks like you Will Have to use quadratic equation
x=-b+/-Square Root of(b^2-4(a)(c))) all of it devided by 2(a)

2+/-{ 144-4(-2)(-14)
2+/-{ 144-112}
2+/-{ 32}
2+/- 4{2}

Now you are at (2+ 4 {2})over -4, and (2- 4 {2}) over -4

I'm sorry but it is somewhat dificult to explain e-mail

Answer 4

-2x² - 12x - 14 =
-2( x² + 6x + 7)

and that's it. if it had been -7, could have gone further.

Answer 5

First of all, they all have a common denominator of 2. So divide each term by 2 and them you will get. -x^2 - 6x - 7

Then you will use the Quadratic formula:

(-b + or - sqrt(b^2-4ac)) / 2a

so you plug it in :

-6 + sqrt(-6^2-4(-1)(-7)) / 2(-1) = -(sqrt(2)-3)

then again

-6 - sqrt(-6^2-4(-1)(-7)) / 2(-1) = (sqrt(2) - 3)

Answer 6

tak out -2

-2 (x^2 + 6x + 7)

it can't be factored any further.

Answer 7

-2(x^2+6x+7) is the farthest u can go

Answer 8

I use to do this in sixth grade! what grade r u in ?
it depens... do you have to leave your answer in turms of x?