How do you solve this for x?

1 ⤊

How do you solve this for x?

[3x^2]-6x=0

2007-04-11 08:01:31 · 4 answers · asked by Nicky 2 in Education & Reference ➔ Homework Help

4 answers

3x^2-6x=0
3x(x-2)=0
3x=0
x-2=0
x=0 x=2

2007-04-11 08:11:01 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

Well,

Move the 6x to the other side:
3x^2=6x

divide by 3x:
x=2

2007-04-11 15:09:57 · answer #2 · answered by Martin L 3 · 1⤊ 0⤋

first divide by the common multiple of 3. This leaves you with x^2-2x=0. Then factor out the x. That leaves you with x*(x-2). So your answers are 0 and 2. You will always have as many answers as your highest power.

2007-04-11 15:13:34 · answer #3 · answered by wildstar_2 6 · 0⤊ 0⤋

3x^2-6x=0
3x^2=6x
(3x^2)/x= (6x)/x
3x=6
x=6/3
x=2

2007-04-11 15:08:40 · answer #4 · answered by Preeti 2 · 0⤊ 0⤋