An airplane is flying in a horizontal circle at a speed of 105m/s. The 80.0kg pilot does not want his centripetal acceleration to exceed 7.00 times free-fall acceleration.
A. What is the minimum radius of the circular path?
B. At this radius, what is the NET force that maintains circular motion exerted on the pilot by the seat belts, the friction between him and the seat, and so forth?
2007-04-11 07:56:25 · 1 answers · asked by oscarjr1990 2 in Science & Mathematics ➔ Physics
Holy cow...7 g's? As a retired aviator, I really have a problem with a 7 g pull.
A. The minimum R can be found by F = ma = m(v^2/R) = mG [See source.]; so that when v = 105 m/sec and G = 7g, we have v^2/R = 7 and R = [(105)^2]/7 in meters. You can do the math.
B. There are four forces in equilibrium. Weight and the force of the chair on the pilots butt are equal and opposite keeping the pilot at constant altitude. And centrifugal and centripetal forces are equal and opposite keeping the pilot at R. Thus, the net forces (f) are zero by inspection. Why? Because if f <> 0 there would be acceleration up or down,or changes in R.
2007-04-11 08:31:23 · answer #1 · answered by oldprof 7 · 0⤊ 0⤋