Geometry: someone help me find the missing side of the two figures?

Question

http://tinypic.com/view.php?pic=400dq8y

Click link to see the two figures (multiple choice for both of them)

Answer 1

Pythagorean Theorem

c² = a² - b²

a = 6

b = 8

√c² = ± √(6)² + (8)²

√c² = ± √36 + 64

√c² = ± √100

c = ± 10

- - - - - - - - -
c² = a² + b²

c² - b² = a². . .Use this formula

let

b = 24

c = 25

± √(25)² - (24)² = √a²

± √625 - 576 = √a²

± √49 = √a²

± 7 = a

Answer 2

You can find the missing sides using the Pythagorean theorem, which says, for a right triangle with hypotenuse 'c' and sides 'a' and 'b':

a^2 + b^2 = c^2

So, for figure 1:

6^2 + 8^2 = c^2
100 = c^2
c = 10

You can also quickly solve this problem by noting that we are dealing with a 3-4-5 triangle, so the third side will be 10.

For figure 2:

a^2 + 24^2 = 25^2
a^2 = 49
a = 7

Answer 3

the first is a 3-4-5 right triangle, by inspection the big side is 2 times 5 equals 10,

the second is 25 ^2 - 24 ^2 = 49
the sqrt of 49 is ?

Answer 4

Use the Pythagorean theorem in each case.
The first answer is 10, the second 7.

Answer 5

C and C