write an equation of a line that contains the point (4,-5) and is parallel to y=-3x+5 write the equation in?

Question

write an equation of a line that contains the point (4,-5) and is parallel to y=-3x+5 write the equation in slope intercept form


Help me!!!!!!!!!!

Answer 1

Slope - intercept form:
y = mx + c

m ... slope
c ... y-intercept

Two parallel lines have the same slope!
If a line is to be parallel to the line y=-3x+5, its slope is -3:

m = -3

y = -3x + c

To find out c, plug the coordinates of the point into the equation.
(x, y) = (4,-5) so
-5 = -3·4 + c
c = -5 + 12
c = 7

Equation of the line you're looking for:

y = -3x + 7

Hope this helps!

Answer 2

use slope intercept form:

y = mx + b

m = slope
b = y-intercept

a line that is parallel to y=-3x+5 would have the same slope so we know the new equation will be

y = -3x + b

to find "b" we need to plug those points (4,-5) into the equation and solve for "b"

-5 = -3(4) + b
-5 = -12 + b
7 = b

so plug the value of "b" into our new equation in which we already found the slope and you have the answer:

y = -3x + 7

note: if you were finding a line that was perpendicular you would take the negative reciprical of the old slope (in this case that would be 1/3)

Answer 3

Since it is parallel the slopes are the same since it needs to cross (4,-5)
y = -3x + b
-5 = -3(4) + b
- 5 = -12 + b
b = 7
y = -3x + 7 is slope intercept form.

Answer 4

Slope intercept Form

y = mx + b

ordered pair

(4, - 5)

- 5 = - 3(4) + b

- 5 = - 12 + b

- 5 + 12 = - 12 + b = + 12

7 = b

y = - 3x + 7

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