2007-04-11 02:51:30 · 7 answers · asked by Justin M 1 in Science & Mathematics ➔ Physics
the bowling ball i think.
its bigger so its not moving as fast
plus smaller things hurt more with the same amount of force 'coz its more concentrated in a smaller space.
2007-04-11 02:56:51 · answer #1 · answered by Chris E 2 · 1⤊ 0⤋
remember safer to seize potential, which one will take much less tension to deaccelerate to 0 velocity. If the strain is in simple terms too intense it incredibly is going to shatter your hand. remember velocity does not kill you, deacceleration kills you. because of the fact that KE = a million/2 mv^2 And F = ma = m (dv/dt) You gotta anticipate the bowling ball has extra mass. however the baseball is going swifter. because of the fact the bowling ball is approximately 6 kg and a baseball is .15 kg it comes all the way down to how briskly ( or sluggish ) you are able to deaccelerate the ball. Your deacceleration time is around a million/10th of a 2nd.
2016-12-09 00:04:38 · answer #2 · answered by cegla 4 · 0⤊ 0⤋
Not a well formulated question as they both might be equally dangerous if the baseball was travelling faster than a speeding bullet, for example.
However, the bowling ball would be more dangerous if you fumbled the catch and dropped it on your foot.
2007-04-11 04:34:51 · answer #3 · answered by lawomicron 4 · 0⤊ 0⤋
assuming the same KE the bowling ball would seem a better choice as the same amount of force would be spread across a larger surface area upon impact.
2007-04-11 02:58:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Suppose tha the baseball is the lighter ball.
It is safer to catch the lighter ball.
Both have same KE =>
m1v1^2 = m2v2^2 = 2E
Since m1 > m2
v1 < v2
m1v1 = 2E/v1
m2v2 = 2E/v2
2E/v1 > 2E/v2
=> m1v1 > m2v2
but m1v1 = F1t
m2v2 = F2t
=> F1 > F2
Or the impact of the heavier ball is more. So its safre to catch the lighter ball , i am assuming baseball is lighter.
2007-04-11 03:00:43 · answer #5 · answered by Nishit V 3 · 0⤊ 0⤋
Both are Unsafe as they have the same Kinetic Energy.
But, I would prefer to catch the Baseball.
2007-04-11 02:56:00 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I would say neither, but the bowling ball would be much slower...
KE(baseball) = KE(bowling ball)
mv^2 = mv^2
0.15v(baseball)^2 = 5v(bowling ball)^2
v(baseball) ~ 6v(bowling ball)
2007-04-11 03:04:45 · answer #7 · answered by gebobs 6 · 0⤊ 0⤋