plz include different wave lengths and different crystals. When I shine my lazar into my crystal it glows red. I guess the light is bouncing around in there and some leaks out. What else is happening in there. Could the crystal be used as a detector for communication transmitted in the lazar beam?
2007-04-11 01:10:57 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
It's to late to correct my spelling " laser" please don't let that distract you.
2007-04-11 01:33:06 · update #1
There is a frequency dependence for this answer. For visible light, the main effects are reflection on the surface of the crystal, and refraction upon entering and leaving the crystal. There is also some dispersion from irregularities and impurities in the crystal.
For shorter wavelengths (like X-rays), there will also be reflections off of the planes of atoms in the crystal. This is called Bragg reflection and is used to study the distribution of atoms in the crystal.
BTW, the term is laser: Light Amplification by Stimulated Emission of Radiation.
2007-04-11 01:21:48 · answer #1 · answered by mathematician 7 · 1⤊ 0⤋
Each crystaline formation oscillates at a frequency that is unique to that crystal, like a fingerprint. Since the magnetic field being introduced to the crystaline matrix causes the atomic structure to react like a switch turning on an off or redirecting electrical flow in the matrix. This is called hall effect, and is used quite frequently in automobile ignition systems, to energize coil packs, and also in the explaning of Electromotive force. I believe the crystal being used in Hall effect switches is a thin slice of Gallium crystal
2007-04-14 06:45:52 · answer #2 · answered by hilltopobservatory 3 · 0⤊ 0⤋
You're only seeing the light bouncing around and diffusing. There's nothing magic about it. Semiconductors are efficient light detectors. Crystals are pretty bad for that purpose.
2007-04-11 01:36:40 · answer #3 · answered by Gene 7 · 0⤊ 1⤋