How do you factor this trinomial: 6p(squared)+5p-6?

Question

Please help!!!

Answer 1

6p^2 + 5p -6 = 6p^2 + 9p -4p - 6
= 3p(2p+3) - 2(2p+3)
= (3p-2)(2p+3).

The general way to do this for a binomial of the form
ax^2+bx+c is to multiply 'a' and 'c' and then select the factors of the product 'ac' in such a way that their sum equals 'b'.

In this example, ac = -36 = 9*(-4) and the sum of the two factors = 5. Thus, we can split the binomial as shown above, and taking the common factors out and grouping similar terms together gives us the result.

Answer 2

6p² + 5p - 6

The middle term is + 5p

find the sum of the middle term

Multiply the first term 6 by the last term 6 equals 36 and factor.

The factors of 36 =

1 x 36
2 x 18
3 x 12
4 x 9. . . .<=. .use these factors
6 x 6

+ 9 and - 4 satisfy the sum of the middle term

insert + 9p and - 4p into the equation

6p² + 5p - 6

6p² + 9p - 4p - 6

3p(2p + 3) - 2(2p + 3)

(3p - 2)(2p + 3)

- - - - - - - - - - - -s-

Answer 3

6p^2+5p-6
(3p-2)(2p+3)

Answer 4

6p^2 + 5p - 6
= (3p - 2)(2p + 3)