cos35sin55 + sin35cos55
numbers are in degrees
help?
2007-04-10 19:47:33 · 7 answers · asked by Rusty 1 in Science & Mathematics ➔ Mathematics
Remember that sin(A + B) = sinAcosB + cosAsinB
Therefore:
cos 35 sin 55 + sin 35 cos 55
= sin 35 cos 55 + cos 35 sin 55
= sin (35 + 55)
= sin 90
= 1
2007-04-10 19:54:59 · answer #1 · answered by ako_talaga_ito 2 · 2⤊ 0⤋
cos35sin55 + sin35cos55 =
(cos35)(sin55) + (sin35)(cos55) =
(0â819 152 044...)(0â819 152 044...) + (0â573 576 436...)(0â573 576 436...) =
(0â671 010 071...) + (0â328 989 928) = 1
2007-04-11 03:12:48 · answer #2 · answered by Brenmore 5 · 0⤊ 0⤋
sin(A + B) = sinAcosB + cosAsinB
cos 35 sin 55 + sin 35 cos 55
= sin (35 + 55)
= sin 90 = 1.
Q.E.D
2007-04-11 03:06:13 · answer #3 · answered by prey of viper 3 · 0⤊ 0⤋
sin(35+55)=sin35cos55+cos35sin55
=sin90
=1
2007-04-11 03:16:22 · answer #4 · answered by Hanbiao 1 · 0⤊ 0⤋
use the formula
sin (A+B) = (sinAcosB) + (sinBcosA)
Here A= 55 & B=35
so ans. sin90
i.e. =1
2007-04-11 03:03:01 · answer #5 · answered by know it 2 · 0⤊ 0⤋
(cos35)(sin55) + (sin35)(cos55)
= (cos35)[cos(90-55)] + (sin35)[sin(90-55)]
= cos²35° + sin²35° = 1
2007-04-11 03:05:30 · answer #6 · answered by Northstar 7 · 0⤊ 0⤋
sin(A+B) = sinA*cosB + cosA*sinB
Your answer is sin(35+55)= sin(90) = 1
2007-04-11 03:03:14 · answer #7 · answered by gp4rts 7 · 0⤊ 0⤋