Hi
I did post this question before but removed it as i typed it incorrectly when i posted it .
i have posted a similar question but this one is different.
I would like to find out how to solve this problem,
Let f(x) =6x+4 if x is less than 3 and also equal sqrt 6(x-3) if x is greater than or equal to 3
then why is the function not continuous out of the following below
though both left and right limits exist at x = 3, they are not equal.
the right limit does not exist at x = 3.
though the limit at x = 3 exists, the value of the limit is not equal to the value of the function at x = 3
the left limit does not exist at x = 3.
None of the above
thanks for your help, it is much appreciated :)
2007-04-10
19:10:03
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2 answers
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asked by
zz06
3
in
Science & Mathematics
➔ Mathematics