A. hydrogen
B. Sulfur
C. Oxygen
D. any of these
2007-04-10 18:20:01 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
OK theres
% = sum of the weight of element/molecular mass of sulfuric acid x 100%
As sulfuric acid is H2SO4
It has 2 H, 1 S and 4 O
Now calculate the molecular weight of H2SO4 and the total weight of H, S and O and place in the equation.
2007-04-10 18:27:15 · answer #1 · answered by Mr Hex Vision 7 · 0⤊ 0⤋
H2 S O4
H2 = 2 amu
S = 32 amu
O4 = 16*4=64 amu It's the oxygen, letter C.
2007-04-11 01:25:23 · answer #2 · answered by ecolink 7 · 0⤊ 0⤋
C. Oxygen
4 molecules at just under 16 amu = 64
1 sulfur molecule at just over 32 amu = 32
2 Hydrogen molecule at just over 1 amu = 2
64/98 = .6536 or 65.36%
2007-04-11 01:27:52 · answer #3 · answered by Rainman 5 · 0⤊ 0⤋
Do your own homework.
H2SO4
This tells you that in a 1 molar solution, there is 2 grams of Hydrogen(1 gram per mol), 32 grams of sulfur(32 grams per mol) and 64 grams of oxygen(16 grams per mol x 4)
Total them all up and you get 98 grams per mol of sulfuric acid.
Divide 64(oxygen) by the total weight - 98 grams an you get = 65.3%
Do your own homework.
2007-04-11 01:28:19 · answer #4 · answered by Bjorn 7 · 0⤊ 0⤋