What you have to do is make all of the fractions have a common denomenator, meaning, the same number at the bottom.
You can do this by multiplying the top number and bottom number in a fraction to get a higher number.
For example, the first one...
Your denomenators are 10, 5, and 8. The lowest common multiple of those three numbers (the lowest whole number that those can all go into easily) is 40. I did that by multiplying 8 by 5, and then it happened to also work for 10.
So, you then multiply Y by 4 (like you do the 10 to get 40), and the 2 by 8 (like you do the 5 to get 40) and the 3 by 5 (like you do the 8 to get 40). Since now all of your fractions have the denomenator of 40, the laws of algebra say that you can ignore the fraction, and just have 4*Y=16+15.... Solve for Y, and you get 31/4.
That method will work for all of those. Good luck.
2007-04-10 17:29:35
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answer #1
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answered by Anonymous
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I'm not really clear on what you are looking for here... but here goes:
Y/10 = 2/5 + 3/8
I'll solve for y
multiply through by 10
y = (2*10) / 5 + (3*10) / 8
=20/5 + 30/8
lowest common denominator is 40, so multiply as follows:
y = 20/5 * 8/8 + 30/8* 5/5
= 160/40 + 150 / 40
=310/40 = 31/4
For 1/4 - 5/6, consider the lowest common denominator is 12, so
1/4 - 5/6 = 1/4 * 3/3 - 5/6*2/2
=3/12 - 10/12 = -7/12 .... I think something is mssing in your question.
3/8 + 1/3 has the lowest common deniominator 24 so
3/8 + 1/3 = 3/8 * 3/3 +1/3* 8/8
= 3/24+ 8/24 = 11/24 Again, there is no"y" to solve for in your equation???
5/8 - 2/5= 1/Y
Multiply through by "y"
1 = 5/8y - 2/5y
again, lowest common denominator is 40 so
1 = (5/8)*(5/5)*y - (2/5)*(8/8)*y
1 = 25/40 y - 16/40 y
1 = 9/40 y
and
y = 1* 40/9 = 40/9 = 4 and 4/9
2007-04-10 17:33:15
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answer #2
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answered by Anonymous
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Y/10 = 2/5 + 3/8
= (2×8 + 3×5) / (5×8)
= 31/40
So Y = 10 × 31/40 = 31/4.
The variable seems to be missing in the next two equations. I can't work out what they were supposed to be.
5/8 - 2/5 = 1/Y: LCD on left is 40
<=> (5×5 - 2×8) / 40 = 1/Y
<=> 9/40 = 1/Y
<=> Y = 40/9.
2007-04-10 17:29:40
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answer #3
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answered by Scarlet Manuka 7
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First put you're variables on one side, and regular number on the other (in fracton from)
Y/10 = 2/5 + 3/8 (this one was already set up)
next find a least common deminator for the right hand side. In this case, it is 40 becasue both 5 and 8 are factors of 40
Y/10 = (2*8)/40 + (3*5)/40
Work out the right hand side to one number
Y/10 = 16/40 + 15/40
Y/10 = (16+15)/40
Y/10 = 31/40
Finally, to get the variable "y" by itself, multiply both sides by 10
(10*Y)/10 = (10*31)/40
Cancle out you're 10's on the left hand side, and reduce the right hand side
Y= 310/40
Y=31/4
That's it. You left out the variables on the next three problems, so I can't help you.
Fourth Problem:
Same beginning setup. Find Least common deminator and add the number together.
(5*5)/40 - (2*8)/40 = 1/Y
(25-16)/40 = 1/Y
9/40 = 1/Y
Now, to get "y" on the left hand side, multiply both sides by Y
y*(9/40) = 1
(9Y)/40 = 1
Now multiply both sides by 40 and divide by 9 to get "y" by itself
Y = 40/9
Hope this helps!
2007-04-10 17:40:12
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answer #4
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answered by ThisIsntMe 3
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a million. worry-unfastened denominator on left hand area of the equation: [x-a million - (x+3)] / (x-a million)(x+3) (x-a million-x-3) / (x^2 + 2x - 3) -4 / (x^2 + 2x - 3) 2. Now the equation is: -4 / (x^2 + 2x - 3) = (x+a million) / (x^2 + 2x - 3) The denominators are the comparable, as a results of fact of this we require: -4 = x+a million -4 = x+a million x = -5
2016-10-21 14:28:33
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answer #5
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answered by ? 4
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Are you clear about LCM (Lowest Common Multiple) of two or more numbers ? That's the key.
2007-04-10 17:40:47
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answer #6
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answered by ag_iitkgp 7
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