Calculating the # of calories of heat energy?

Question

I need help with this Chem problem:
Calculate the number of calories of heat energy required to change the temperature of 5.0-gm of water from 21.1 to 29.3 degrees celcius.

thanks for the help.

is the specific heat of water 1? that's what has me confused....

Answer 1

it takes 1 calorie to heat 1 gram of water 1 degree.
energy=amount of water * delta temperature * specific heat
5,0 * (29,3-21,1) * 1 = 41 calories.
if it was jule, then the specific heat = 4,1
okay Norrie 4,184 then.

Answer 2

That makes no sense "divide it by 1000 then multiply that by 100" is just a pointless way to divide by 10 btw Anyway, the energy stored in a peanut can be calculated properly with the calorie content, which is about 588kcal per 100 grams

Answer 3

Heat = change in temp x mass x specific heat
Heat = 8.2 x 5 x 1
Heat = 41 calories


(i think)

Answer 4

5*1*(29.3-21.1) = 41 calories

Answer 5

You need 1 of what! i.e. The specific heat of water is 1cal/g and also 4.184 J/g.

Your question:...ΔT = 29.3 - 21.1 = 8.2°C
8.2 x 5g x 1cal = 41cal.

(Also: 8.2 x 5 x 4.184 = 171.5Joules)

Good luck.