How do I calculate Instantaneous speed?

Question

I have searched the internet and couldn't find a simple answer. Any feedback on this? Perhaps a more easier version of this for pre-calc?

Answer 1

If you have a graph of a function with position on the y-axis, and time on the x-axis, draw line tangent to the function at the time you're interested in. The slope of this tangent line is the instantaneous speed.

Answer 2

If you have the displacement curve where Y is the distance traveled and X is time, then all you need to do is to find the slope of the curve to determine the speed.

In calculus, this is called the first derivative.

If all you have is the acceleration curve where Y is the instantaneous acceleration and X is time, you would take the area under the curve and add the initial speed.

In calculus, this is called the integral.

It would be helpful to know what information you actually have.

Answer 3

that's difficult to describe without calculus. i visit anticipate you recognize generally used velocity and velocity. utilising acceleration, in case you have an merchandise that starts off at relax and hastens with a relentless acceleration (a), the fee at an instant in time (t), would be (a)(t). If acceleration isn't consistent, that's not that straightforward and you often use calculus in line with a function that describes the acceleration. utilising place, in case you have an merchandise with a relentless velocity/velocity, you are able to basically take 2 factors and use the version in place divided by skill of the version in time. back, if the fee isn't consistent, you often use calculus in line with a function that describes the situation, yet whilst the factors are very close at the same time, you will get an spectacular estimate.

Answer 4

If you know the position as a function of time, the instantaneous speed is the first derivative of this function.

x = f (t) => position as a function of time.

v = dx/dt = f'(t)

This is correct, assuming it moves along the x axis.

What if something is moving in a curve, like on a circle?
Then it has components of velocity in both x and y dimensions, and the speed is merely the root sum of the squares.

Speed = sqrt [ (dx/dt)^2 + (dy/dt)^2]

Answer 5

Jump off a fast-moving motorcycle in an experiment?

Answer 6

i think you have to find the derivative of the equation and then plug in the value of time that you are looking for

Answer 7

you cant calculate it... its instantaneous! you know like the word instantly.

Answer 8

Very quickly.