Help with logarithms and exponents?

Question

how do you solve for x?

3^(7x-12)=5^(x-7)

Answer 1

Take log of both sides
(7x-12)log3 = (x-7)log5
so x(7log3-log5)=12log3-7log5
and x=(12log3-7log5)/(7log3-log5)=
=0.3153
(check calculations)