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pigs, black Bfur is dominant toalbino and rough R coat is dominant to smooth. the 2 genes assort indeendently, A black-rough coated and albino-rough coated produce a lttler containing several albino-smooth coated offspring
a. give genotypes of black-rough coated parent
b. give the genotype of albino-rough coated parent
c. determine the phenotype ratio expected in offspring of these parents
thanks in advance

2007-04-10 14:51:49 · 3 answers · asked by jennifer 2 in Science & Mathematics Biology

3 answers

Since B (black) and R (rough) are dominant, if the black-rough parent were homozygous, all the offspring would be black-rough. Therefore, the answer to a is BbRr. Because albino is recessive, the albino parent must be bb. It has a rough coat, but again, if it were homozygous, all the offspring would be rough. Thus, since there are smooth offsprint, the answer to b must be bbRr. To cross the two parents, you do a Punnett square of BbRr x bbRr. The offspring are: black rough-3; black smooth-1; and albino rough-3; albino smooth-1.

2007-04-10 15:04:09 · answer #1 · answered by kt 7 · 0 0

a) BBRR or BbRr
b) bbrr
c) either 1:1 black- rough coated (if it is BBRR) or 1 black-rough: 1 black smooth: 1 albino rough: 1 albino smooth (if its BbRr)

..i think, im not sure about c

2007-04-10 22:08:25 · answer #2 · answered by Anonymous · 0 0

a) Bb Rr
b)bb Rr

Bb RR 2/16=.125
Bb Rr 4/16 = .25
Bb rr 2/16 = .125
bb RR 2/16 = .125
bb Rr 4/16 = .25
bb rr 2/16 = .125

2007-04-10 22:03:50 · answer #3 · answered by alikasams 2 · 0 0

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