an object is placed on a rough floor and given an initial velocity of 15 m/s?

Question

it then slides 25 m before coming to rest. the coeficient of kinetic friction between the object and the floor is

Answer 1

In this case all of the kinetic energy will be lost to the work of friction

.5*m*v^2=m*g*µ*d
µ=v^2/(2*g*d)
=15^2/490
=.46

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