The current I in electrical conductor varies inversely as the resistance R of the conductor. Suppose I is 0.2 amperes when the resistance is 200 ohms. What is the current when the resistanc eis 250 ohms?
2007-04-10 13:56:26 · 6 answers · asked by JJ 1 in Science & Mathematics ➔ Mathematics
Voltage = Current * Resistance
V=IR
V = .2 * 200
V = 40
V/R = I
40/250 = .16 amps
2007-04-10 14:00:17 · answer #1 · answered by Paul T 2 · 1⤊ 0⤋
V = IR
V = 0.2 A * 200 ohms
V = 40 volts
the new value for R is 250 ohms
I = V / R
I = 40 volts / 250 ohms
I = 0.16 A
2007-04-10 14:05:48 · answer #2 · answered by Angelico B 2 · 0⤊ 0⤋
4
2007-04-10 13:59:30 · answer #3 · answered by bombaybubba 3 · 0⤊ 2⤋
IR = constant, mathematical description of inverse proportion
(0.2)(200) = I(250)
Solve for I,
I = 0.16 amperes
2007-04-10 14:02:54 · answer #4 · answered by sahsjing 7 · 1⤊ 0⤋
I = k / R k = R I = 501 x 2 = 1002 I = 1002 / 844 A I = 1.2 A
2016-05-17 06:43:42 · answer #5 · answered by ? 3 · 0⤊ 0⤋
I = k/r
0.2 = k/200
k= .2*200 = 40
So I = 40/r
When r = 250,
I = 40/250 = .16 amperes
2007-04-10 14:03:29 · answer #6 · answered by ironduke8159 7 · 0⤊ 1⤋