What is the speed of this crate?

Question

A crate of mass 13.0 kg is pulled up a rough incline with an initial speed of 1.50 m/s. The pulling force is 100 N parallel to the incline, which makes an angle of 20.0° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 5.95 m. The change in kinetic energy of the crate is 50.26 J.

What is the speed of the crate after being pulled 5.95 m?

Answer 1

Okay here we go

Change in kinetic energy is dKe
dKe=Ke2-Ke1=50.26=.5mv2^2 - .5m v1^2)
v2=sqrt(2 dKe/m +v1^2)=sqrt(2 x 50.26/13 + (1.5)^2)= v2=3.16m/sec