look for two numbers that multiply to 30 and add to -13
-3 and -10
6x^2 - 3xy - 10xy + 5y^2
factor by groups
(6x^2 - 3xy) + (-10xy + 5y^2)
take out 3x and -5y
3x(2x-y) + -5y(2x - y)
take out 2x -y
(2x-y) (3x-5y)
2007-04-10 13:53:23
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answer #1
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answered by 7
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factoring???
multiply 6 and 5 to give you 30
what numbers multiplied together give you 30?
1, 30
2, 15
3, 10
5, 6
-1 , -30
-2, -15
-3, -10
-5, -6
which pair of factors added together gives you -13?
well -3 and -10
so we age going to rewrite the original polynomial as:
6x^2 - 3xy - 10xy + 5y^2
apply grouping:
(6x^2 - 3xy)+( - 10xy + 5y^2)
find GCF of each parenthesis:
3x(2x - y) -5y(2x - y)
(2x - y)(3x - 5y)
2007-04-10 13:58:28
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answer #2
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answered by Ana 4
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look for two numbers that multiply to 30 and add to -13
-3 and -10
6x2 - 3xy - 10xy + 5y2
factor by groups
(6x2 - 3xy) + (-10xy + 5y2)
take out 3x and -5y
3x(2x-y) + -5y(2x - y)
take out 2x -y
(2x-y) (3x-5y)
2007-04-10 13:57:33
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answer #3
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answered by mikey_cardinals_lucy 1
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What's the question? Do you want to factor it?
(3x+1y)(2x-5y)
2007-04-10 13:54:24
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answer #4
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answered by bz2hcy 3
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(ax +by)(cx+dy) = acx^2 + (ad+bc)xy + bdy^2
ac= 6
bd=5
ad+bc= - 13
a = 2
c = 3
b = -1
d = -5
(2x - y)(3x -5y)
2007-04-10 15:05:35
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answer #5
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answered by Anonymous
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(3x-5y)(2x-y)
6x^2-3xy-10xy+5y^2
6x^2-13xy+5y^2
2007-04-10 14:21:49
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answer #6
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answered by Dave aka Spider Monkey 7
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(3x +1y)(2x - 5y)
2007-04-10 13:54:18
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answer #7
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answered by ecolink 7
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