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2007-04-10 13:50:11 · 7 answers · asked by nephroyti 2 in Science & Mathematics Mathematics

7 answers

look for two numbers that multiply to 30 and add to -13

-3 and -10

6x^2 - 3xy - 10xy + 5y^2

factor by groups
(6x^2 - 3xy) + (-10xy + 5y^2)

take out 3x and -5y
3x(2x-y) + -5y(2x - y)

take out 2x -y

(2x-y) (3x-5y)

2007-04-10 13:53:23 · answer #1 · answered by      7 · 1 0

factoring???
multiply 6 and 5 to give you 30
what numbers multiplied together give you 30?
1, 30
2, 15
3, 10
5, 6
-1 , -30
-2, -15
-3, -10
-5, -6
which pair of factors added together gives you -13?
well -3 and -10
so we age going to rewrite the original polynomial as:

6x^2 - 3xy - 10xy + 5y^2

apply grouping:
(6x^2 - 3xy)+( - 10xy + 5y^2)

find GCF of each parenthesis:
3x(2x - y) -5y(2x - y)
(2x - y)(3x - 5y)

2007-04-10 13:58:28 · answer #2 · answered by Ana 4 · 0 0

look for two numbers that multiply to 30 and add to -13

-3 and -10

6x2 - 3xy - 10xy + 5y2

factor by groups
(6x2 - 3xy) + (-10xy + 5y2)

take out 3x and -5y
3x(2x-y) + -5y(2x - y)

take out 2x -y

(2x-y) (3x-5y)

2007-04-10 13:57:33 · answer #3 · answered by mikey_cardinals_lucy 1 · 0 0

What's the question? Do you want to factor it?
(3x+1y)(2x-5y)

2007-04-10 13:54:24 · answer #4 · answered by bz2hcy 3 · 0 0

(ax +by)(cx+dy) = acx^2 + (ad+bc)xy + bdy^2
ac= 6
bd=5
ad+bc= - 13

a = 2
c = 3
b = -1
d = -5

(2x - y)(3x -5y)

2007-04-10 15:05:35 · answer #5 · answered by Anonymous · 0 0

(3x-5y)(2x-y)

6x^2-3xy-10xy+5y^2
6x^2-13xy+5y^2

2007-04-10 14:21:49 · answer #6 · answered by Dave aka Spider Monkey 7 · 0 0

(3x +1y)(2x - 5y)

2007-04-10 13:54:18 · answer #7 · answered by ecolink 7 · 0 0

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