English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

i need help with this problem. please help with soltion and answer.

Find the domain of f(x)= square root of x-3 divided by x+1

2007-04-10 13:10:29 · 10 answers · asked by Leosphere 2 in Science & Mathematics Mathematics

10 answers

you can't have a negative square root, so x has to be greater than or equal to 3. you also can't have the denominator be 0, so x != -1 (but that's already taken care of by being greater than 3)

so... domain is x >= 3

2007-04-10 13:15:20 · answer #1 · answered by IK 2 · 1 0

Note first that domain is all possible x values. Range is all possible y values.

Note second, there is a square root. Square roots can never be taken of a negative number nor a negative answer.

Note third, x+1 cannot be equal to zero, because it is not possible to divide by zero... at least not in algebra.

By the third note, x+1 cannot equal zero, x cannot equal negative one.

By the second note, x-3 cannot be less than 0. x cannot be less than 3.

By the second note, top cannot be negative, x >=3. The minimum value of y is going to be when x=3, because when x increases, y increases (can test). Solving for x=3, y=0.

By the last note, y>=0 is range, domain is x>=3.

2007-04-10 13:51:27 · answer #2 · answered by christianprogrammer2 4 · 0 0

Your question is ambiguous. Is it (sqrt(x-3)) / (x+1), or is it sqrt((x-3)/(x+1))? I will assume that it's the former, so the denominator is not under the square root.

Since you can't divide by zero, x=-1 is excluded.

Since you can't take the square root of a negative number, x<3 is excluded.

Hence, the domain consists of all real numbers >= 3.

2007-04-10 13:17:04 · answer #3 · answered by Bramblyspam 7 · 2 0

well you know you cant have 0 in denominator so x can never be -1. if you want only real numbers than x cannot be less than 3, but it can be 3.

so your domain would be [3,infinity)

the square bracket means include, since 3 is ok.

2007-04-10 13:15:21 · answer #4 · answered by ytrewq 3 · 0 0

domain of f(x) = squareroot(x-3) / (x+1) :

restrictions: x - 3 can not be a negative number
x + 1 can not be zero

Dom f = {x / x >= 3 and x != -1)

or simply

Dom f = {x / x >= 3} (since x > 3 implies x != -1)

2007-04-10 13:26:59 · answer #5 · answered by Angelico B 2 · 0 0

The domain is x greater then or equal to 3.

2007-04-10 13:15:31 · answer #6 · answered by bruinfan 7 · 0 0

the domain in this case is whatever x can't be which is (-1) because then it'll make the bottom equal to zero, making the equation impossible to solve.

2007-04-10 13:15:32 · answer #7 · answered by Smartie 3 · 0 1

Why could you upload the two pounds to the 27 the adult adult males paid? the adult adult males paid 30 and are due back 5, if each purely gets back a million, they are at the same time nonetheless owed 2. you may desire to subtract the two from the adult adult males's 27, and understand there continues to be 5 downstairs. the two pounds the bellboy gets are from what the adult adult males paid.

2016-10-21 14:01:39 · answer #8 · answered by ? 4 · 0 0

den not = 0
domain all reals except 0,
num, x > = 3

Domain x > = 3

2007-04-10 13:13:27 · answer #9 · answered by richardwptljc 6 · 1 0

3x2x1+9

2007-04-10 13:15:35 · answer #10 · answered by Jill 1 · 0 2

fedest.com, questions and answers