Find the distance between the points (-1.4,2.2) and (-1.2,3.4)?

Question

Round your answer to the nearest tenth

Answer 1

First, let's look at the x-coordinates.
Going from -1.4 to -1.2, the x-coordinate have changed by 0.2

Next, let's look at the y-coordinates.
Going from 2.2 to 3.4, the y-coordinates have changed by 1.2

Then use Pythagoras to determine the distance between the points.

The square of the distance equals (0.2)^2 + (1.2)^2 = 1.48
So the distance is sqrt(1.48) = 1.21655, which rounds to 1.2. That's your answer.

The answer of 1.2 is slightly misleading in that it implies that the hypotenuse of a triangle is the same length as one of its legs. Of course the hypotenuse is actually longer; the misleading part is caused by rounding error.

Answer 2

-1.2 - - 1.4 = 0.2
3.4 - 2.2 = 1.6
0.2 and 1.6 are the cathetus from a rectangle triangle whose hypotenuse is the distance you are looking for.

h^2 =a^2 + b^2
h^2 = 0.04 + 2.56 = 2.60
h = 1.61245.....

Answer 3

graph those two points, then use the pythagoryan theory to solve for the distance

Answer 4

d = distance = sqrt( x2- x1)^2 +( y2 -y1)^2

with (-1.4;2.2) and (-1.2; 3.4)


d = sqrt(-1.2 -(-1.4))^2 + (3.4 -2.2)^2

= sqrt (0.2)^2 + (1.2)^2

= sqrt (0.04 + 1.44)

= sqrt (1.48)

= 1.2165

= 1.2

Answer : 1.2

Answer 5

d = sq rt [(-1.2 - - 1.4)^2 + (3.4 - 2.2)^2]
d = sq rt[(0.2)^2 + (1.2)^2] = 1.48

d = sq rt 1.48 = sq rt 1.5

Answer 6

sqrt( (-.2)^2+(-1.2)^2)=sqrt(1.48)=1.216 (approximately)