What magnitude of F2 is required to apply the required 500-N force (F1) to the nail? (ignore weight of hammer)

Question

A claw hammer is used to pull a nail out of a board. The nail is at an angle of 60 degrees to the board, and a force F1 of magnitude 500 N applied to the nail is required to pull it from the board. The hammer head contacts the board at point A, which is 0.080 m from where the nail enters the board. A horizontal force F2 is applied to the hammer handle at a distance of 0.300 m above the board.

http://session.masteringphysics.com/problemAsset/1008098/4/yf_Figure_11_30.jpg

I figured it out. The Torque on the handle is equal to the torque of the claw. So, .300m * F2=.080m * F1sin(60). F2=115N

Answer 1

Not enough information. Don't know the angle of the hammer handle or the location of the contact point between the claw and the nail (which may be sticking partway out from the board and would be in real life).