Find the area of a parallelogram with the given vertices.?

Question

P(1, 3), Q(3, 3), R(7, 8), S(9, 8)

Answer 1

Area of paralellogram = Base x Height

Base = 3-1 =2
Height = 8-3 =5

Area =5 x 2= 10

Answer 2

base is 3-1 = 2, height is 8-3 = 5, so area = 2(5) = 10

Answer 3

First, hit upon the scale of the aspects. PQ = squareroot((a million-3)^2+(3-3)^2). formulation for distance, squareroot((x1-x2)^2+(y1-y2)^2). attempt this for both element of the parallelogram. you'll rather get 2 lengths, or perchance only one. Multiply both lengths, or basically the single by using employing itself, and that is your section.

Answer 4

First, find the length of the sides. PQ = squareroot((1-3)^2+(3-3)^2). Formula for distance, squareroot((x1-x2)^2+(y1-y2)^2). Do this for each side of the parallelogram. You will only get two lengths, or even just one. Multiply the two lengths, or just the one by itself, and that's your area.

Answer 5

You + Mathbook = Answer