Math problem?

0 ⤊

having trouble with conjugates:

6/ 2 - square root of 3

help appreciated!

2007-04-10 12:26:44 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

the conjugate is 6/2+sqrt3 and its product is
36/4-3 = 6

2007-04-10 12:30:57 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

The conjugate is for the denominator only and is
2 + sq rt 3. When you multiply, you get
6(2+ sq rt3) /1 or 12 + 6 sq rt 3

2007-04-10 19:34:06 · answer #2 · answered by richardwptljc 6 · 0⤊ 0⤋