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√√256 + √√√6561 + 8^⅓

2007-04-10 12:01:29 · 4 answers · asked by abs of steel 3 in Science & Mathematics Mathematics

4 answers

Simplify

4th root of 256 = 4

8th root of 6561 = 3

cubed root of 8 = 2

add together to get 9.

2007-04-10 12:08:01 · answer #1 · answered by Cady 1 · 0 0

√√256 + √√√6561 + 8^⅓
= 256^1/4 + 6561^1/8 +8^1/3
= 4 + 3 +2 = 9

2007-04-10 12:09:44 · answer #2 · answered by ironduke8159 7 · 0 0

√√256 = 4th root of (256)
√√√6561 = 8th root of (6561)
8^(1/3) = 2


4th root of (256) = 4th root of ( 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2)

8th root of (6561)
= 8rh root of (3 × 3 × 3 × 3 × 3 × 3 × 3 × 3)

4 + 3 + 2 = 9

2007-04-10 12:09:17 · answer #3 · answered by      7 · 0 0

4+3+2=9

2007-04-10 12:04:55 · answer #4 · answered by leo 6 · 1 0

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