How do you factor X^3 + 4x^2 - x - 4 ???

Answer 1

x^3 + 4x² - x - 4 =
x²(x + 4) - 1(x + 4) =
(x² - 1)(x + 4) =
(x + 1)(x - 1)(x + 4)

Answer 2

The answer is (x-1)(x+4)(x+1). Basically you first want to replace x with a number so when entered into the equation, you will get zero as ur final answer. This is done by trial and error but is very quick.

When you put x=1 into the equation you get an end results of 0. This means (x-1)=0. You therefore then do long division by (x-1) and you will get x^2 + 5x + 4 which is (x+4)(x+1). The 3 brackets are your factors.

Answer 3

X^3 + 4x^2 - x - 4

factor by groups

(x^3 + 4x^2) + (-x - 4)

take out x^2 and -1

x^2(x+4) + -1(x+4)

take out x +4

(x+4) (x^2-1)

factor further

(x+4) (x+1) (x-1)

Answer 4

x^2(x+ 4) -(x +4) = (x^2 - 1)(x+4) = (x-1)(x+1)(x+4)

If the sum of the coefficients is 0, then the expression has 1 as a root. If the sum of the coefficient of x^3 and x is equals to the sum of the other ones, the expression has root -1

Ana

Answer 5

x^3 + 4x^2 - x- 4 = x^2(x + 4) -(x+4) = (x+4)(x^2 -1)=
=(x+4)(x+1)(x-1) OK!

Answer 6

1 is obviously a root so divide by x-1
(x-1)(x^2 +5x+4) other factors are now obvious
(x-1)(x+1)(x+4)