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The x intercepts of a parabola are located at (-3,0) and (4,0). What is the x-coordinate of the vertex?

2007-04-10 10:33:50 · 4 answers · asked by ggg 1 in Science & Mathematics Mathematics

4 answers

Assuming that the axis of symmetry of the parabola is a vertical line, then the x-coordinate of the vertex will be the midpoint between x = -3 and x = 4.

x = (-3 + 4)/2 = 1/2 = 0.5

2007-04-10 10:49:04 · answer #1 · answered by Travis G 1 · 0 0

The vertex has x coordinate =1/2(a+b) where a and b are the x intercepts.
so Xv= (-3+4)/2 =1/2

2007-04-10 11:15:46 · answer #2 · answered by santmann2002 7 · 0 0

it really is truly extremely straightforward! because that it really is a quadratic and also you're given the x-Int., you are able to upload both x coordinates at the same time then divide by technique of two. you may do this because parabolas are symmetrical, and the x coordinate of the vertex will consistently be contained in the technique the x intercepts. (3+5)/2 = 4

2016-12-03 19:35:24 · answer #3 · answered by ? 4 · 0 0

if the axis of symetry of ur parabola parallel to y axis then x-coordinate of the vertex will be =(4+(-3))/2=0.5

2007-04-10 10:38:46 · answer #4 · answered by Ceaser 2 · 0 0

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