math???? please help?

Question

c^2+4c-m^2=0

(how many real solutions)
(explain why the discriminant is positive for n )

if (v) is not equal to 0 and (b) is not equal to 0 and v^2+2vb+b^2 what is the ratio of v to b

Answer 1

1). The discriminant is 16 + 4m².
Since m² is always nonnegative, the
minimum value of this expression is 16, so
it's always positive. So your equation always
has 2 real solutions.

2). v²+2bv+b² = (v+b)², but the right side
of your equation is missing. Can't determine
such a ratio from the equation given. Sorry!