Quadratic Formula?

Question

How do I solve this using the quadratic formula....

X*(squared) + 2X =48

Answer 1

Quadratic formula

x = - b ± √b² - 4ac /2a

x² + 2x = 48

x² + 2x - 48 = 48 - 48

x² + 2x - 48 = 0

let

a = 1

b = 2

c = - 48

- - - - - -

x = - 2 ± √(2)² - 4(1)(- 48) / 2(1)

x = - 2 ± √4 - (- 192) / 2

x = - 2 ± √4 = 192 / 2

x= - 2 ± √196 / 2

x = - 2 ± 14 / 2

- - - - - - - - - - - -

Solving for + roots

x = - 2 + 14 / 2

x = 12 / 2

x = 6

- - - - - - - - - - - -

Solving for - roots
x = - 2 - 14 / 2

x = - 16 / 2

x = - 8

- - - - - - - - - s-

Answer 2

The easiest way to solve the equation is to factor into
(x+8)(x-6) which means the values for x are -8 and 6. Using the quadratic formula x = {-b+/- sqrt(b**2-4ac)}/2a where a = 1, b = 2, and c = -48. This simplifies to {-2 +/- sqrt(196)}/2 or -1 +/- 7 or +6 or -8. QED.

Answer 3

x = 6, -8

The only steps are to subtract the 48 from each side so you have the equation in the standard quadratic form* and then substitute the equation's values into the formula for the roots of a quadratic equation.

* That standard form for this problem would then look like this:

1x^2 + 2x + (-48) = 0 { ax^2 + bx + c = 0 }

Answer 4

x^2 +2x -48 =0
(x-6)(x+8) =0
x=6
x=-8

to use the quaratic formula:

x=(-2 +/-sqrt(4+192))/2
x=(-2 +/- 14)/2
x=-8
x=6

Answer 5

put in form

ax^2 + bx +c = 0

then put in formula

(-b + or - square root (b^2 - 4ac) ) / 2a

(-2 + or - sqrt (4+ 192) / 2

(-2 + or - 14)/2
(-2+14)/2 or 6
(-2-16)/2 or -8

Answer 6

make it x^2 + 2x - 48 = 0
a b c

-b +or - the square root ( b^2 - 4(a)(c))
-----------------------------------------------------
2(a)


that is the equation, the line repersents that your suppose to divide the top by 2(a).

-2 + or - SQroot ( 2^2 - 4(1)(-48))
----------------------------------------------
2(1)


= -2 + or - 14
--------------------
2

= -8 or 6