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Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number.


x + 4 – 8x – 1 > 3(x – 2)

2007-04-10 07:02:50 · 6 answers · asked by cougarhw 1 in Science & Mathematics Mathematics

6 answers

x + 4 - 8x - 1 > 3(x - 2)

- 7x + 3 > 3x - 6

- 7x + 3 + 7x > 3x - 6 + 7x

3 > 10x - 6

3 + 6 > 10x - 6 + 6

9 > 10x

9 / 10 > 10x / 10

9 / 10 > x

- - - - - - - - - -s-

2007-04-10 07:52:39 · answer #1 · answered by SAMUEL D 7 · 0 0

x + 4 – 8x – 1 > 3(x – 2)

combine terms on left and disrtibute the 3 on the right
-7x + 3 > 3x - 6

subtract 3x from both sides
-10x + 3 > -6

subtract 3 from both sides
-10x > -9

divide by -10 and switch the inequality sign (because you're dividing by a negative number) and get
x < 9/10

Hope this helps!

2007-04-10 14:09:11 · answer #2 · answered by jewls_1_3 2 · 1 0

Let's solve this step by step:

Given:

x+4-8x-1 > 3(x-2)

Simplifying the left side and expanding the right side, we get:

-7x+3 > 3x-6
-7x+3+7x+6>3x+7x-6+6
9>10x

Dividing by 10 on both sides, we get:

9/10 > x or
x < 9/10

2007-04-10 14:47:25 · answer #3 · answered by TrustRegainedFriendshipRestored 2 · 0 0

x>1
x+4-8x-1>3(x-2)
Simplify the inequality
-7X+3 > 3x-6
Collect like terms
-10x>-9
divide by coeffecent
(-10x)/-10 > -9/-10
gives the answer
x<9/10

Which mean any value of x greater then one will make the inequality true

2007-04-10 14:12:47 · answer #4 · answered by good_guynot79 1 · 0 0

expand
x+4-8x-1>3x-6
combine
-7x+3=3x-6
subtract 3x from each side
subtract 3 from each side
-10x>-9
divide both sides by -10 (since negative switch > sign to <)
x<-9/10

2007-04-10 14:08:57 · answer #5 · answered by Maverick 7 · 0 1

with so many instructions u cud have solved it urself
-10x > -9
x<9/10

2007-04-10 14:09:52 · answer #6 · answered by Maths Rocks 4 · 0 0

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