solve the equation for b : 11\12 + b= 5\6
2007-04-10 07:01:26 · 7 answers · asked by nataliehlmz2008 1 in Science & Mathematics ➔ Mathematics
Since 11/12 is begin added to b, you need to subtract it from both sides of the equation to "undo" it.
11/12 + b = 5/6
11/12 + b = 10/12 (get a common denominator of 12 for both fractions)
-11/12 -11/12 (add the top of the fractions and keep the bottom the same)
b = -1/12
2007-04-10 07:06:12 · answer #1 · answered by T F 4 · 0⤊ 0⤋
11/12 + b = 5/6
-11/12 + b = -11/12
b= -11/12 + 5/6
b= -11/12 + 10/12
b= -1/12
2007-04-10 14:08:55 · answer #2 · answered by sweety 2 · 0⤊ 0⤋
To be absolutely clear, I am going to rewrite your equation as: (11/12) + b = (5/6). (I expect this is what you mean.)
Knowing 5/6 equals 10/12, you get:
11/12 + b = 10/12.
So, the answer is ( - 1/12). negative one twelfth.
2007-04-10 14:10:10 · answer #3 · answered by Sithara B 2 · 0⤊ 0⤋
b= -1/12
2007-04-10 14:17:48 · answer #4 · answered by harold. 4 · 0⤊ 0⤋
-1/12 = b
2007-04-10 14:05:18 · answer #5 · answered by John Smith 2 · 0⤊ 0⤋
11\12 + b= 5\6
b = 5/6 - 11/12
common denominator is 12
b = 10/12 - 11/12
b = -1/12
Hope this helps!
2007-04-10 14:05:27 · answer #6 · answered by jewls_1_3 2 · 0⤊ 0⤋
11/12 + b = 5/6
12(11/12) + 12(b) = 12(5/6)
11 + 12b = 10
11 + 12b - 11 = 10 - 11
12b = - 1
12b / 12 = - 1 / 12
b = - 1/12
- - - - - - - - -s-
2007-04-10 14:58:03 · answer #7 · answered by SAMUEL D 7 · 0⤊ 0⤋