I'm in the middle of getting together example problems and answers for a trigonomety project. I have found a good example but I am not sure if I have solved it correctly. I would really appreciate it if someone could help me out by solving the problem. Thank you.
The problem that I am using is number 8 on this website.
http://www.mth.msu.edu/~drachman/math106spring01/lec15_right_angle_trigonometry_homework.pdf
2007-04-10 06:21:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
By the way, when I solved this I got the answer of 466.6 ft.
2007-04-10 06:40:30 · update #1
The dotted line is also 300 feet long.
x + y = height of the smokestack
tan(50) = x/300
x = tan(50) * 300 = 357.52607777826298761159242155813 ft.
tan(20) = y/300
y = tan(20) * 300 = 109.19107027986070840531436483305 ft.
x + y = 466.71714805812369601690678639118 ft.
2007-04-10 06:35:40 · answer #1 · answered by Dave 6 · 1⤊ 0⤋
After leaving an airport, a airplane flies for a million.5h at a velocity of 200km/h on a procedure 2 hundred ranges. Drawing a vector starting up on the muse of an x-y graph, 200º will look contained in the third quadrant, 20º less than the -x axis. The length of this vector = 200km/h * a million.5h = 300km The x element of this vector = three hundred * sin20º = ? The y element of this vector = three hundred * cos20º = ? because that this vector is contained in the third quadrant, both elements will be adverse in value. Then, on a procedure 340 ranges, the airplane flies for 2h at a velocity of 250km/h. The length of this vector = 250km/h * 2h = 500km Drawing a vector starting up on the muse of an x-y graph, 340º will look contained in the 4th quadrant, 20º less than the +x axis The x element of this vector = 500 * sin20º = ? The y element of this vector = 500 * cos20º = ? because that this vector is contained in the 4th quadrant, the x element will be useful and the y element will be adverse. next, algebraically upload both x elements to get an x resultant (your including 2 negatives) Then algebraically upload both y elements to get a y resultant (you're including a adverse and an excellent) Your very last equation is, (distance of airplane from airport)² = (x resultant)² + (y resultant)² hint: 300km < (distance of airplane from airport) < 350km
2016-12-03 19:15:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
x.cos 50= 300 so we have 300/cos 50=x
then x= 466.72 this is the longitude of the hyp
the height of the smokestack is 466.72sin 50 = h = 357.52
The height of the building is 300sin 20 + 357.52 = 460.13
2007-04-10 06:39:59 · answer #3 · answered by goofy 1 · 0⤊ 0⤋
Tan = opp/a = opposite / adjacent side.
You are given the adjacent side to each angle as 300 ft.
Therefore a=300.
For the top section: tan (20 deg) = 0.3640 (lookup table)
0.3640 = opp/a = opp/300
opp = 109.2 ft (top part of stack)
For lower section: tan (50 deg) = 1.192 (lookup table)
1.192 = opp/a = opp/300
opp = 357.5 ft
Smokestack total height = 109.2+357.5 = 466.7 ft
2007-04-10 06:41:19 · answer #4 · answered by rwhitehead837 2 · 0⤊ 0⤋
The bottom and the top of the building is 300 feet away from the smokestack
tanθ = y /x
tan20 = y / 300
300tan20 = 300(y/300)
300tan20 = y
300(0.363970234) = y
109.1910703 = y
109.2 feet = y
The height of the smokestack is 109.2 feet
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2007-04-10 07:35:27 · answer #5 · answered by SAMUEL D 7 · 0⤊ 1⤋