Algebra Word Problem...?

Question

Can anyone figure this out?
. Translate to an algebra statement; do not solve:
Three times the difference of five and a twice a number yields the same result as the same number increased by four.

Answer 1

let number be x
then
3(5-2x)=x+4
hope it works

Answer 2

three times= 3*
difference of five and..., where ...=x, is 5-x, keep that to the side
twice an number= 2*y (where y is the number)
yields = "="
the number increased by four= y+4

put it all together now. remember that your x is the second part of the statement.

3(5-2x) = x+4 (I'm just replacing x with y, here)

Answer 3

The difference of five is: t - 5
three times the difference is: 3 * (t - 5)

z = 3 (t - 5)

Twice a number yields: 2z =

As the same number increased by four: t + 4

Therefore,
z = 3 (t - 5)
2z = t + 4

I think.

Answer 4

let x be the number. Then,

3(5 - 2x) = x + 4

Answer 5

3(2x-5) = x+4

Answer 6

3*(2x - 5) = x + 4

Answer 7

If the scholars cutting-edge grade is a ninety% then we’re of direction assuming it’s out of a hundred% ninety/a hundred Now because of the fact the scholars grade stronger 20% from the final grading era then you definately upload that to the previous a hundred% offering you with ninety/ a hundred and twenty = .75 and because grades are in probabilities you multiply .75 via a hundred offering you with 75% because of the fact the scholars previous grade

Answer 8

3(5-2x)=x+4

Btw.. x=11/7 :)

Answer 9

3(5x-2x)=x+4

Answer 10

3(5x-2x)=x+4