In a right triangle with the hypotenuse c=10 and the angle A=50 degrees, the side b equals....?

Answer 1

sinθ = y / r

sin50 = y / 10

10sin50 = 10(y/10)

10sin50 = y

10(0.766044443) = y

7.660444431 = y

7.7 rounded to one decimal place

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Answer 2

If I understand the problem correctly -
Side A can be found using the equation

cos 50 = A/10
or
A = 10 cos 50

Side B can then be found using

A^2 + B^2 = C^2

Answer 3

The angle opposite the hypotenuse c is angle C (That's the way it should be written).

So angle C = 90 degrees. (Angle opposite hypotenuse)
Angle B = 40 degrees

AC = side b

Cos 50 = b/c
0.64 = b/10
b = 0.64*10
b = 6.4 (approximate)

Note: Cos 50 = 0.64 is approximate.

Answer 4

see b/c = sin 50(degrees)
so find value of sin50
replace it in the above equation,
b/10 = sin 50
b = 10 X (value of sin 50)

Answer 5

Angle b is 40 degrees (180-90-50).
Thus use the law of sines, sin(b)/b=sin(c)/c
Solve for b to get b=c*(sin(b)/sin(c))
c=10, sin(40)=0.643, sin(90)=1
Thus b=10*.643=6.43