Algebra and Trig question. Please show work. Serious replies only! Thankyou so much!?

Question

Find one of the solutions of x = (square root of 3x -12 ) + 4

a).7
b). -4
c).-3
d).5

Answer 1

x = sqrt(3x - 12) + 4
x - 4 = sqrt(3x - 12)
(x - 4)^2 = 3x - 12
x^2 - 8x + 16 = 3x - 12
x^2 - 11x + 28 = 0
(x - 4)(x - 7) = 0
x = 4 or x = 7
Answer A.

Answer 2

x=(squareroot of 3x-12)+4
subtract 4 from both sides
x-4 = (square root of 3x-12)
square both sides
(x-4)^2 = 3x-12
expand (x-4)^2 to get :x2 -8x+16
x2-8x+16 =3x-12
x2-11x+28=0
look for 2 numbers such that their sum=-11 and product=+28
these are ; -4 and -7
x2-4x-7x+28=0
x(x-4)-7(x-4)=0
(x-4)(x-7)=0
either x=7 or x=4

so one of the answers= (a) 7

Answer 3

x-4 = sqr(3x-12)
square each side
x^2-8x+16=3x-12
Bring right hand side over
x^2-8x-3x+16+12=0
simplify
x^2-11x+28=0
use formula
11+-sqr(121-112) whole over 2
simplifys to 14/2 or 8/2
=7 or 4
Hence a is the answer.

Answer 4

when we say square root it is positive

so we try 7 and 5

by putting we see that 7 satisfies the equation

LHS = 7 RHS squareroot(21-12) + 4 = square root(9) + 4 = 3+4 = 7

so that is the ans

Answer 5

enable x be the "different" attitude. Then the 1st attitude could be 2x-15. Complementary angles upload as much as ninety stages. So the equation reads x + (2x-15) = ninety. Simplify, 3x-15 = ninety. upload 15 to the two facets, 3x = a hundred and five. Divide the two facets by skill of three, x = 35. that's the smaller attitude. the 1st attitude is 2x35-15, that's fifty 5 stages. that's the better attitude, so "c" is the respond.

Answer 6

x square=3x-12 +16
x square=3x +4
x square -3x -4=0
x= 4 or -1
do it the splitting them middle term and it will come corectly
u will c