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4 answers

If tall is dominant (T) and short is recessive (t) as in peas:

Parents: TT x Tt
Gametes: T T and T t
F1: TT, Tt, TT, Tt
All tall

2007-04-08 18:33:25 · answer #1 · answered by ecolink 7 · 0 0

TT(tall-true breeding) x Tt(heterozygous)
the genotype of the offsprings will be
TT(tall-true breeding)
Tt(tall- haterozygous)
this is called a 'back-cross' where the F1 generation is crossed with the parent.
phenotypically all the plants will be tall unless it's a case of incomplete dominance.
genotypically-
homozygous D:heterozygous
1:1

2007-04-08 20:53:57 · answer #2 · answered by rara avis 4 · 0 0

Your question is a touch incomplete, yet i imagine i can make out what you're asking. Mendel crossed tall and short flora, yet all of their offspring were tall flora. This replaced into because the tall trait replaced into dominant over the quick trait. The flora contained in the F1 technology could have all been heterozygous (Aa) for his or her correct.

2016-11-27 20:42:10 · answer #3 · answered by ? 4 · 0 0

If T=tall and t=short (I am assuming this the other phenotype)
True breeding tall means TT (ture breeding short is tt, its just so you know its not a herterozygous (or hybrid) cross (Tt).)

TT X Tt
That means your crosses are TT, Tt, TT, Tt. So all plants are tall, 50% are true breeding (or homozygous dominant) and 50% are herterozygous or hybrid type

2007-04-08 18:36:46 · answer #4 · answered by mareeclara 7 · 0 0

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