Make a mathematical statement using one of four digits (2,4,6,8) that equals a listed fraction (1/5,etc.)?

Question

An example: 1/3 (the listed fraction) = 2/(2+2+2)
You must use the given digit (2,4,6, or 8) four times in a mathematical statment like the one above. I need answers for the following fractions using all the digits: (1/5, 1/7, 1/9, 1/11, 1/13, 1/15, 1/17, 1/19, 1/21, 1/31, 1/51, 1/101) Need response ASAP...

An example: 1/3 (the listed fraction) = 2/(2+2+2)
You must use the given digit (2,4,6, or 8) four times in a mathematical statment like the one above. I need answers for the following fractions using all the digits: (1/5, 1/7, 1/9, 1/11, 1/13, 1/15, 1/17, 1/19, 1/21, 1/31, 1/51, 1/101) Can't use #^-1. You can use square roots or powers: Ex:
21=3^3-3-3 or 8= √(8+8) + √(8+8)

MUST USE THE SAME DIGIT FOUR TIMES...

Answer 1

(1/5, 1/7, 1/9, 1/11, 1/13, 1/15, 1/17, 1/19, 1/21, 1/31, 1/51, 1/101)

1/5 = 6 / (6*6 - 6)
1/7 = 6 / (6 + 6*6)
1/9 = 8 / (8*8 + 8)
1/11 = (6+6 - 6/6)^-1
1/13 = (6+6 + 6/6)^-1
1/15 = (8+8 - 8/8)^-1
1/17 = (8+8 + 8/8)^-1
1/19 = (4! - 4 - 4/4)^-1
1/21 = (4! - 4 + 4/4)^-1

Answer 2

1/7 = 4 / ((2*6)+8)
1/7 = 4 / ((6+8)*2)
1/9 = 2 / (4+6+8)
1/11 = 2 / ((6*4)-2)
1/13 = 2 / ((6*4) +4)
1/15 = 4 / ((2+8)*6)
1/17 = 2/((6*6)-2)
1/19 = 4 / (6*2*8)
1/21 = 2 / ((4*8) - 6)
1/31 = 1 / ((8*4)-(2/2))
1/51 =
1/101 =

Answer 3

Well i got some different ones nobody else has so far:

1/11 = 4/44 = 4/[4! * 4^1/2 -4]

1/13 = 2/26 = 4^1/2/[4! - 4^1/2 + 4]

1/15 = 2/30 = 4^1/2/[4! + 4^1/2 + 4]

You're getting closer!

Answer 4

1/5 = 6/30 = 6/(6*6-6) or 4/20 = 4/(4*4+4)

1/7 = 6/(6*6+6) or 8/(8*8-8)

1/9 = 8/(8*8+8)

1/11 = (sqrt 2 * sqrt 2) / 22 or (sqrt 4 * sqrt 4) / 44 or (sqrt 6 * sqrt 6) / 66 or (sqrt 8 * sqrt 8) / 88


1/15 = 4 / {[(sqr 4) * 4] - 4}
1/17 = 4 / {[(sqr 4) * 4] + 4}

Answer 5

you need to artwork on the products in parenthesis first. in simple terms so: a. Parenthesis: (a million+2) = 3 b. such that 6 divide 2(3) c. Multiply: 2(3) = 6 d. such that 6 divide 6 e. Equals a million be conscious: Order of operation: PEMDAS (parenthesis, exponents, multiiplication, branch, addition, subtraction)