work and steps please
a surveyor is standing 50' from the base of a large tree. The surveyor measures the angle of elevation to the top of the tree as 71.5 degrees. how tall is the tree?
2007-04-08 15:31:04 · 6 answers · asked by k 1 in Science & Mathematics ➔ Mathematics
Call h the height of the tree. Then tan 71.5 = h/50, or h = 50 * tan 71.5 = 50 * 2.99, about 150 feet.
2007-04-08 15:39:01 · answer #1 · answered by Anonymous · 0⤊ 1⤋
1. draw a right triangle the horizontal leg is the distance of 50', label the acute angle up from the horizontal 71.5 degrees, this is the angle of elevation, and label the vertical leg x, this is the tree.
2. Use the tangent function to set up the equation: tan 71.5 degrees = x/50
3. Solve the equation by multiplying both sides by 50 to get 50tan71.5 = x
4. calculate x to be approximately 149.43 feet tall
2007-04-08 22:39:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Draw the picture.
tree height = (50 ft + tree trunk radius) tan 71.5 degree
2007-04-08 22:38:31 · answer #3 · answered by Mark 6 · 0⤊ 0⤋
Tan (angle) = Opposite/Adjacent
Tan(71.5) = Height of tree/ 50 feet
50 * Tan(71.5) = height of tree
2007-04-08 22:35:44 · answer #4 · answered by babyducktravel 1 · 0⤊ 0⤋
tree height = 50Tan71.5 = 149.43 feet
2007-04-08 22:37:13 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
babyducktravel got the right steps
ans is 3. rounded off.
the number is something like 2.988684963
2007-04-08 22:36:21 · answer #6 · answered by ong_joce 2 · 0⤊ 1⤋