Which statement must be true?

Question

Which statement must be true if a parabola represented by the equation y = ax2 + bx + c does not intersect the x-axis?

Answer 1

b^2 -4ac is negative
or b^2 - 4ac < 0

Answer 2

Even though you didn't type it in, I can give you the correct statement.
The parabola y = ax^2 +bx+c has x-intercepts at the x values where 0 = ax^2 + bx + c (all x-intercepts have a y coordinate of zero).
If the parabola has no x-intercepts, there are no real solutions to the equation ax^2 + bx + c = 0.
Using the quadratic formula, the solutions of the equation are
x = (-b+sqrt(b^2-4ac))/2a and x = (-b-sqrt(b^2-4ac))/2a.
These will be real solutions so long as the value under the radical is not negative. Therefore, there will be no real solutions when the value under the radical is less than zero (negative).

So, y = ax^2 + bx + c will have no x-intercepts when
b^2 - 4ac < 0.
NOTE: b^2 - 4ac is called the discriminant of the formula.

Answer 3

in simple terms a is needed. which will require a number of the others, besides, yet they don't seem absolute. A tiny rocket would attain get away speed without very large engines, as an social gathering, and they under no circumstances deliver a lot of more advantageous gasoline.

Answer 4

The roots of the equation are imaginary.

Answer 5

what??