ok. i just posted this question, but i kind of need to restate it.
9m^2-36m+40=0
i know that you have to use the quadratic formula, but the only reasonable answers that i can give are:
(6-2i)/3 , (6+2i)/3
or
[6- (2sqrt of 7i)]/3 , [6+ (2sqrt of 7i)]/3
which answer is it?
2007-04-08 14:51:26 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The first one.
9m^2 - 36m + 40 = 0
a = 9, b = -36, c = 40
m = [36 +/- sqrt(36^2 - 4(9)(40))] / (2*9)
m = [36 +/- sqrt(-144)] / 18
m = [36 +/- i*sqrt(144)] / 18
m = [36 +/- 12i] / 18
m = 36/18 +/- 12i/18
m = 2 +/- 2i/3 or
m = (6 +/- 2i)/3
2007-04-08 14:55:51 · answer #1 · answered by Anonymous · 0⤊ 0⤋
m=(( 36 +-sqrt(-144)/18 = 2+- 2i/3
The right answer is the first one
2007-04-08 21:57:37 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
(6-2i)/3 or (6+2i)/3
2007-04-08 21:57:48 · answer #3 · answered by ong_joce 2 · 0⤊ 0⤋