Anyone know how to do this. x^2 + 2x + 1 <= 0 using the priniciples of zero products.?

Question

x^2 + 2x + 1 <= 0.

Principles of zero products involves polynomials/ rational inequlities and testing)

Answer 1

x^2 + 2x + 1 <= 0

Factor the left hand side. It is a perfect square trinomial.

(x + 1)^2 <= 0

Here's the thing; square numbers are ALWAYS greater than or equal to 0, so it follows that

(x + 1)^2 >= 0

In order for (x + 1)^2 to be less than or equal to 0 AND greater than or equal to 0, it must mean (x + 1) EQUALS 0.

x + 1 = 0
x = -1

Answer 2

This is (x+1)^2 which is always >0 except at x= -1 where it is 0
So the only solution is x=0

Answer 3

first you factor and get (x+1)^2<= 0
so when you plug in any number, your answer will always be postive except for -1so you that the only possible answer is -1 becIf you test for example with -3 then you ause it comes out to be = to 0. Try plugging in anyother number and get (-2)^2= 4 so not good or plugg in 3 then you get 4^2= 16 which is also not negative.