Alkali metal hydroxides are sometimes used to "scrub" excess carbon dioxide from the air in closed spaces (such as submarines and spacecrafts). For example, lithium hydroxide reacts with carbon dioxide according to the unbalanced chemical equation.
LiOH(s) + CO2(g) Li2CO3(s) + H2O(g)
Suppose a lithium hydroxide cannister contains 155 g of LiOH(s). What mass of CO2(g) will the cannister be able to absorb?
grams?
If it is found that after 24 hours of use the cannister has absorbed 106 g of carbon dioxide, what percentage of its capacity has been reached?
%?
2007-04-08 13:41:32 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Balancing the equation, you have
2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(g)
M(CO2) / M(2LiOH) = 12.01 + 2*16 / 2(6.941 + 16 + 1.008
M(CO2) / M(2LiOH) = 44.01 / 47.898
x / 44.01 = 155 / 47.898
x = 155*44.01 / 47.898
x = 142.4183 g CO2
106*100 / 142.4183 = 74.42866%
2007-04-08 17:00:25 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋